Class Solution


  • public class Solution
    extends Object
    1848 - Minimum Distance to the Target Element.

    Easy

    Given an integer array nums (0-indexed) and two integers target and start, find an index i such that nums[i] == target and abs(i - start) is minimized. Note that abs(x) is the absolute value of x.

    Return abs(i - start).

    It is guaranteed that target exists in nums.

    Example 1:

    Input: nums = [1,2,3,4,5], target = 5, start = 3

    Output: 1

    Explanation: nums[4] = 5 is the only value equal to target, so the answer is abs(4 - 3) = 1.

    Example 2:

    Input: nums = [1], target = 1, start = 0

    Output: 0

    Explanation: nums[0] = 1 is the only value equal to target, so the answer is abs(0 - 0) = 0.

    Example 3:

    Input: nums = [1,1,1,1,1,1,1,1,1,1], target = 1, start = 0

    Output: 0

    Explanation: Every value of nums is 1, but nums[0] minimizes abs(i - start), which is abs(0 - 0) = 0.

    Constraints:

    • 1 <= nums.length <= 1000
    • 1 <= nums[i] <= 104
    • 0 <= start < nums.length
    • target is in nums.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • getMinDistance

        public int getMinDistance​(int[] nums,
                                  int target,
                                  int start)