Class Solution
- java.lang.Object
-
- g2001_2100.s2012_sum_of_beauty_in_the_array.Solution
-
public class Solution extends Object
2012 - Sum of Beauty in the Array.Medium
You are given a 0-indexed integer array
nums
. For each indexi
(1 <= i <= nums.length - 2
) the beauty ofnums[i]
equals:2
, ifnums[j] < nums[i] < nums[k]
, for all0 <= j < i
and for alli < k <= nums.length - 1
.1
, ifnums[i - 1] < nums[i] < nums[i + 1]
, and the previous condition is not satisfied.0
, if none of the previous conditions holds.
Return the sum of beauty of all
nums[i]
where1 <= i <= nums.length - 2
.Example 1:
Input: nums = [1,2,3]
Output: 2
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 2.
Example 2:
Input: nums = [2,4,6,4]
Output: 1
Explanation: For each index i in the range 1 <= i <= 2:
-
The beauty of nums[1] equals 1.
-
The beauty of nums[2] equals 0.
Example 3:
Input: nums = [3,2,1]
Output: 0
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 0.
Constraints:
3 <= nums.length <= 105
1 <= nums[i] <= 105
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
sumOfBeauties(int[] nums)
-