Class Solution


  • public class Solution
    extends Object
    2094 - Finding 3-Digit Even Numbers.

    Easy

    You are given an integer array digits, where each element is a digit. The array may contain duplicates.

    You need to find all the unique integers that follow the given requirements:

    • The integer consists of the concatenation of three elements from digits in any arbitrary order.
    • The integer does not have leading zeros.
    • The integer is even.

    For example, if the given digits were [1, 2, 3], integers 132 and 312 follow the requirements.

    Return a sorted array of the unique integers.

    Example 1:

    Input: digits = [2,1,3,0]

    Output: [102,120,130,132,210,230,302,310,312,320]

    Explanation: All the possible integers that follow the requirements are in the output array.

    Notice that there are no odd integers or integers with leading zeros.

    Example 2:

    Input: digits = [2,2,8,8,2]

    Output: [222,228,282,288,822,828,882]

    Explanation: The same digit can be used as many times as it appears in digits.

    In this example, the digit 8 is used twice each time in 288, 828, and 882.

    Example 3:

    Input: digits = [3,7,5]

    Output: []

    Explanation: No even integers can be formed using the given digits.

    Constraints:

    • 3 <= digits.length <= 100
    • 0 <= digits[i] <= 9
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • findEvenNumbers

        public int[] findEvenNumbers​(int[] digits)