Class Solution
java.lang.Object
g0001_0100.s0088_merge_sorted_array.Solution
88 - Merge Sorted Array\.
Easy
You are given two integer arrays `nums1` and `nums2`, sorted in **non-decreasing order** , and two integers `m` and `n`, representing the number of elements in `nums1` and `nums2` respectively.
**Merge** `nums1` and `nums2` into a single array sorted in **non-decreasing order**.
The final sorted array should not be returned by the function, but instead be _stored inside the array_ `nums1`. To accommodate this, `nums1` has a length of `m + n`, where the first `m` elements denote the elements that should be merged, and the last `n` elements are set to `0` and should be ignored. `nums2` has a length of `n`.
**Example 1:**
**Input:** nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
**Output:** [1,2,2,3,5,6]
**Explanation:** The arrays we are merging are [1,2,3] and [2,5,6]. The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.
**Example 2:**
**Input:** nums1 = [1], m = 1, nums2 = [], n = 0
**Output:** [1]
**Explanation:** The arrays we are merging are [1] and []. The result of the merge is [1].
**Example 3:**
**Input:** nums1 = [0], m = 0, nums2 = [1], n = 1
**Output:** [1]
**Explanation:** The arrays we are merging are [] and [1]. The result of the merge is [1]. Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1.
**Constraints:**
* `nums1.length == m + n`
* `nums2.length == n`
* `0 <= m, n <= 200`
* `1 <= m + n <= 200`
*
-109 <= nums1[i], nums2[j] <= 109
**Follow up:** Can you come up with an algorithm that runs in `O(m + n)` time?-
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Solution
public Solution()
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Method Details
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merge
public void merge(int[] nums1, int m, int[] nums2, int n)
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