Class MedianFinder
java.lang.Object
g0201_0300.s0295_find_median_from_data_stream.MedianFinder
295 - Find Median from Data Stream\.
Hard
The **median** is the middle value in an ordered integer list. If the size of the list is even, there is no middle value and the median is the mean of the two middle values.
* For example, for `arr = [2,3,4]`, the median is `3`.
* For example, for `arr = [2,3]`, the median is `(2 + 3) / 2 = 2.5`.
Implement the MedianFinder class:
* `MedianFinder()` initializes the `MedianFinder` object.
* `void addNum(int num)` adds the integer `num` from the data stream to the data structure.
* `double findMedian()` returns the median of all elements so far. Answers within
10-5
of the actual answer will be accepted.
**Example 1:**
**Input**
["MedianFinder", "addNum", "addNum", "findMedian", "addNum", "findMedian"]
[ [], [1], [2], [], [3], []]
**Output:** [null, null, null, 1.5, null, 2.0]
**Explanation:**
MedianFinder medianFinder = new MedianFinder();
medianFinder.addNum(1); // arr = [1]
medianFinder.addNum(2); // arr = [1, 2]
medianFinder.findMedian(); // return 1.5 (i.e., (1 + 2) / 2)
medianFinder.addNum(3); // arr[1, 2, 3]
medianFinder.findMedian(); // return 2.0
**Constraints:**
* -105 <= num <= 105
* There will be at least one element in the data structure before calling `findMedian`.
* At most 5 * 104
calls will be made to `addNum` and `findMedian`.
**Follow up:**
* If all integer numbers from the stream are in the range `[0, 100]`, how would you optimize your solution?
* If `99%` of all integer numbers from the stream are in the range `[0, 100]`, how would you optimize your solution?-
Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionvoid
addNum
(int num) void
balance
(PriorityQueue<Integer> maxHeap, PriorityQueue<Integer> minHeap) double
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Constructor Details
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MedianFinder
public MedianFinder()
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Method Details
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addNum
public void addNum(int num) -
balance
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findMedian
public double findMedian()
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