Class Solution

java.lang.Object
g0501_0600.s0598_range_addition_ii.Solution

public class Solution extends Object
598 - Range Addition II\. Easy You are given an `m x n` matrix `M` initialized with all `0`'s and an array of operations `ops`, where ops[i] = [ai, bi] means `M[x][y]` should be incremented by one for all 0 <= x < ai and 0 <= y < bi. Count and return _the number of maximum integers in the matrix after performing all the operations_. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/10/02/ex1.jpg) **Input:** m = 3, n = 3, ops = \[\[2,2],[3,3]] **Output:** 4 **Explanation:** The maximum integer in M is 2, and there are four of it in M. So return 4. **Example 2:** **Input:** m = 3, n = 3, ops = \[\[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]] **Output:** 4 **Example 3:** **Input:** m = 3, n = 3, ops = [] **Output:** 9 **Constraints:** * 1 <= m, n <= 4 * 104 * 0 <= ops.length <= 104 * `ops[i].length == 2` * 1 <= ai <= m * 1 <= bi <= n
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maxCount

      public int maxCount(int m, int n, int[][] ops)