Class Solution

java.lang.Object
g0601_0700.s0655_print_binary_tree.Solution

public class Solution extends Object
655 - Print Binary Tree\. Medium Given the `root` of a binary tree, construct a **0-indexed** `m x n` string matrix `res` that represents a **formatted layout** of the tree. The formatted layout matrix should be constructed using the following rules: * The **height** of the tree is `height` and the number of rows `m` should be equal to `height + 1`. * The number of columns `n` should be equal to 2height+1 - 1. * Place the **root node** in the **middle** of the **top row** (more formally, at location `res[0][(n-1)/2]`). * For each node that has been placed in the matrix at position `res[r][c]`, place its **left child** at res[r+1][c-2height-r-1] and its **right child** at res[r+1][c+2height-r-1]. * Continue this process until all the nodes in the tree have been placed. * Any empty cells should contain the empty string `""`. Return _the constructed matrix_ `res`. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/05/03/print1-tree.jpg) **Input:** root = [1,2] **Output:** [["","1",""], ["2","",""]] **Example 2:** ![](https://assets.leetcode.com/uploads/2021/05/03/print2-tree.jpg) **Input:** root = [1,2,3,null,4] **Output:** [["","","","1","","",""], ["","2","","","","3",""], ["","","4","","","",""]] **Constraints:** * The number of nodes in the tree is in the range [1, 210]. * `-99 <= Node.val <= 99` * The depth of the tree will be in the range `[1, 10]`.
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    • Solution

      public Solution()
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