Class Solution

java.lang.Object
g0601_0700.s0684_redundant_connection.Solution

public class Solution extends Object
684 - Redundant Connection\. Medium In this problem, a tree is an **undirected graph** that is connected and has no cycles. You are given a graph that started as a tree with `n` nodes labeled from `1` to `n`, with one additional edge added. The added edge has two **different** vertices chosen from `1` to `n`, and was not an edge that already existed. The graph is represented as an array `edges` of length `n` where edges[i] = [ai, bi] indicates that there is an edge between nodes ai and bi in the graph. Return _an edge that can be removed so that the resulting graph is a tree of_ `n` _nodes_. If there are multiple answers, return the answer that occurs last in the input. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/05/02/reduntant1-1-graph.jpg) **Input:** edges = \[\[1,2],[1,3],[2,3]] **Output:** [2,3] **Example 2:** ![](https://assets.leetcode.com/uploads/2021/05/02/reduntant1-2-graph.jpg) **Input:** edges = \[\[1,2],[2,3],[3,4],[1,4],[1,5]] **Output:** [1,4] **Constraints:** * `n == edges.length` * `3 <= n <= 1000` * `edges[i].length == 2` * 1 <= ai < bi <= edges.length * ai != bi * There are no repeated edges. * The given graph is connected.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • findRedundantConnection

      public int[] findRedundantConnection(int[][] edges)