Class Solution

java.lang.Object
g0601_0700.s0690_employee_importance.Solution

public class Solution extends Object
690 - Employee Importance\. Medium You have a data structure of employee information, including the employee's unique ID, importance value, and direct subordinates' IDs. You are given an array of employees `employees` where: * `employees[i].id` is the ID of the ith employee. * `employees[i].importance` is the importance value of the ith employee. * `employees[i].subordinates` is a list of the IDs of the direct subordinates of the ith employee. Given an integer `id` that represents an employee's ID, return _the **total** importance value of this employee and all their direct and indirect subordinates_. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/05/31/emp1-tree.jpg) **Input:** employees = \[\[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1 **Output:** 11 **Explanation:** Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3. They both have an importance value of 3. Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11. **Example 2:** ![](https://assets.leetcode.com/uploads/2021/05/31/emp2-tree.jpg) **Input:** employees = \[\[1,2,[5]],[5,-3,[]]], id = 5 **Output:** -3 **Explanation:** Employee 5 has an importance value of -3 and has no direct subordinates. Thus, the total importance value of employee 5 is -3. **Constraints:** * `1 <= employees.length <= 2000` * `1 <= employees[i].id <= 2000` * All `employees[i].id` are **unique**. * `-100 <= employees[i].importance <= 100` * One employee has at most one direct leader and may have several subordinates. * The IDs in `employees[i].subordinates` are valid IDs.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • getImportance

      public int getImportance(List<Employee> employees, int id)