java.lang.Object
g0601_0700.s0700_search_in_a_binary_search_tree.Solution

public class Solution extends Object
700 - Search in a Binary Search Tree\. Easy You are given the `root` of a binary search tree (BST) and an integer `val`. Find the node in the BST that the node's value equals `val` and return the subtree rooted with that node. If such a node does not exist, return `null`. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg) **Input:** root = [4,2,7,1,3], val = 2 **Output:** [2,1,3] **Example 2:** ![](https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg) **Input:** root = [4,2,7,1,3], val = 5 **Output:** [] **Constraints:** * The number of nodes in the tree is in the range `[1, 5000]`. * 1 <= Node.val <= 107 * `root` is a binary search tree. * 1 <= val <= 107
  • Constructor Details

    • Solution

      public Solution()
  • Method Details