Package g0701_0800.s0732_my_calendar_iii

Class MyCalendarThree

java.lang.Object
g0701_0800.s0732_my_calendar_iii.MyCalendarThree
public class MyCalendarThree extends Object
732 - My Calendar III\. Hard A `k`\-booking happens when `k` events have some non-empty intersection (i.e., there is some time that is common to all `k` events.) You are given some events `[start, end)`, after each given event, return an integer `k` representing the maximum `k`\-booking between all the previous events. Implement the `MyCalendarThree` class: * `MyCalendarThree()` Initializes the object. * `int book(int start, int end)` Returns an integer `k` representing the largest integer such that there exists a `k`\-booking in the calendar. **Example 1:** **Input** ["MyCalendarThree", "book", "book", "book", "book", "book", "book"] [ [], [10, 20], [50, 60], [10, 40], [5, 15], [5, 10], [25, 55]] **Output:** [null, 1, 1, 2, 3, 3, 3] **Explanation:** MyCalendarThree myCalendarThree = new MyCalendarThree(); myCalendarThree.book(10, 20); // return 1, The first event can be booked and is disjoint, so the maximum k-booking is a 1-booking. myCalendarThree.book(50, 60); // return 1, The second event can be booked and is disjoint, so the maximum k-booking is a 1-booking. myCalendarThree.book(10, 40); // return 2, The third event [10, 40) intersects the first event, and the maximum k-booking is a 2-booking. myCalendarThree.book(5, 15); // return 3, The remaining events cause the maximum K-booking to be only a 3-booking. myCalendarThree.book(5, 10); // return 3 myCalendarThree.book(25, 55); // return 3 **Constraints:** * 0 <= start < end <= 109 * At most `400` calls will be made to `book`.

  • Constructor Details

    • MyCalendarThree

      public MyCalendarThree()

  • Method Details

    • book

      public int book(int start, int end)