Class Solution

java.lang.Object
g0701_0800.s0764_largest_plus_sign.Solution

public class Solution extends Object
764 - Largest Plus Sign\. Medium You are given an integer `n`. You have an `n x n` binary grid `grid` with all values initially `1`'s except for some indices given in the array `mines`. The ith element of the array `mines` is defined as mines[i] = [xi, yi] where grid[xi][yi] == 0. Return _the order of the largest **axis-aligned** plus sign of_ 1_'s contained in_ `grid`. If there is none, return `0`. An **axis-aligned plus sign** of `1`'s of order `k` has some center `grid[r][c] == 1` along with four arms of length `k - 1` going up, down, left, and right, and made of `1`'s. Note that there could be `0`'s or `1`'s beyond the arms of the plus sign, only the relevant area of the plus sign is checked for `1`'s. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/06/13/plus1-grid.jpg) **Input:** n = 5, mines = \[\[4,2]] **Output:** 2 **Explanation:** In the above grid, the largest plus sign can only be of order 2. One of them is shown. **Example 2:** ![](https://assets.leetcode.com/uploads/2021/06/13/plus2-grid.jpg) **Input:** n = 1, mines = \[\[0,0]] **Output:** 0 **Explanation:** There is no plus sign, so return 0. **Constraints:** * `1 <= n <= 500` * `1 <= mines.length <= 5000` * 0 <= xi, yi < n * All the pairs (xi, yi) are **unique**.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • orderOfLargestPlusSign

      public int orderOfLargestPlusSign(int n, int[][] mines)