Class Solution

java.lang.Object
g0801_0900.s0809_expressive_words.Solution

public class Solution extends Object
809 - Expressive Words\. Medium Sometimes people repeat letters to represent extra feeling. For example: * `"hello" -> "heeellooo"` * `"hi" -> "hiiii"` In these strings like `"heeellooo"`, we have groups of adjacent letters that are all the same: `"h"`, `"eee"`, `"ll"`, `"ooo"`. You are given a string `s` and an array of query strings `words`. A query word is **stretchy** if it can be made to be equal to `s` by any number of applications of the following extension operation: choose a group consisting of characters `c`, and add some number of characters `c` to the group so that the size of the group is **three or more**. * For example, starting with `"hello"`, we could do an extension on the group `"o"` to get `"hellooo"`, but we cannot get `"helloo"` since the group `"oo"` has a size less than three. Also, we could do another extension like `"ll" -> "lllll"` to get `"helllllooo"`. If `s = "helllllooo"`, then the query word `"hello"` would be **stretchy** because of these two extension operations: `query = "hello" -> "hellooo" -> "helllllooo" = s`. Return _the number of query strings that are **stretchy**_. **Example 1:** **Input:** s = "heeellooo", words = ["hello", "hi", "helo"] **Output:** 1 **Explanation:** We can extend "e" and "o" in the word "hello" to get "heeellooo". We can't extend "helo" to get "heeellooo" because the group "ll" is not size 3 or more. **Example 2:** **Input:** s = "zzzzzyyyyy", words = ["zzyy","zy","zyy"] **Output:** 3 **Constraints:** * `1 <= s.length, words.length <= 100` * `1 <= words[i].length <= 100` * `s` and `words[i]` consist of lowercase letters.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • expressiveWords

      public int expressiveWords(String s, String[] words)