java.lang.Object
g0801_0900.s0883_projection_area_of_3d_shapes.Solution

public class Solution extends Object
883 - Projection Area of 3D Shapes\. Easy You are given an `n x n` `grid` where we place some `1 x 1 x 1` cubes that are axis-aligned with the `x`, `y`, and `z` axes. Each value `v = grid[i][j]` represents a tower of `v` cubes placed on top of the cell `(i, j)`. We view the projection of these cubes onto the `xy`, `yz`, and `zx` planes. A **projection** is like a shadow, that maps our **3-dimensional** figure to a **2-dimensional** plane. We are viewing the "shadow" when looking at the cubes from the top, the front, and the side. Return _the total area of all three projections_. **Example 1:** ![](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/02/shadow.png) **Input:** grid = \[\[1,2],[3,4]] **Output:** 17 **Explanation:** Here are the three projections ("shadows") of the shape made with each axis-aligned plane. **Example 2:** **Input:** grid = \[\[2]] **Output:** 5 **Example 3:** **Input:** grid = \[\[1,0],[0,2]] **Output:** 8 **Constraints:** * `n == grid.length == grid[i].length` * `1 <= n <= 50` * `0 <= grid[i][j] <= 50`
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • projectionArea

      public int projectionArea(int[][] grid)