java.lang.Object
g0801_0900.s0892_surface_area_of_3d_shapes.Solution

public class Solution extends Object
892 - Surface Area of 3D Shapes\. Easy You are given an `n x n` `grid` where you have placed some `1 x 1 x 1` cubes. Each value `v = grid[i][j]` represents a tower of `v` cubes placed on top of cell `(i, j)`. After placing these cubes, you have decided to glue any directly adjacent cubes to each other, forming several irregular 3D shapes. Return _the total surface area of the resulting shapes_. **Note:** The bottom face of each shape counts toward its surface area. **Example 1:** ![](https://assets.leetcode.com/uploads/2021/01/08/tmp-grid2.jpg) **Input:** grid = \[\[1,2],[3,4]] **Output:** 34 **Example 2:** ![](https://assets.leetcode.com/uploads/2021/01/08/tmp-grid4.jpg) **Input:** grid = \[\[1,1,1],[1,0,1],[1,1,1]] **Output:** 32 **Example 3:** ![](https://assets.leetcode.com/uploads/2021/01/08/tmp-grid5.jpg) **Input:** grid = \[\[2,2,2],[2,1,2],[2,2,2]] **Output:** 46 **Constraints:** * `n == grid.length == grid[i].length` * `1 <= n <= 50` * `0 <= grid[i][j] <= 50`
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • surfaceArea

      public int surfaceArea(int[][] grid)