java.lang.Object
g1001_1100.s1018_binary_prefix_divisible_by_5.Solution

public class Solution extends Object
1018 - Binary Prefix Divisible By 5\. Easy You are given a binary array `nums` ( **0-indexed** ). We define xi as the number whose binary representation is the subarray `nums[0..i]` (from most-significant-bit to least-significant-bit). * For example, if `nums = [1,0,1]`, then x0 = 1, x1 = 2, and x2 = 5. Return _an array of booleans_ `answer` _where_ `answer[i]` _is_ `true` _if_ xi _is divisible by_ `5`. **Example 1:** **Input:** nums = [0,1,1] **Output:** [true,false,false] **Explanation:** The input numbers in binary are 0, 01, 011; which are 0, 1, and 3 in base-10. Only the first number is divisible by 5, so answer[0] is true. **Example 2:** **Input:** nums = [1,1,1] **Output:** [false,false,false] **Constraints:** * 1 <= nums.length <= 105 * `nums[i]` is either `0` or `1`.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • prefixesDivBy5

      public List<Boolean> prefixesDivBy5(int[] nums)