Class Solution

java.lang.Object
g1001_1100.s1049_last_stone_weight_ii.Solution

public class Solution extends Object
1049 - Last Stone Weight II\. Medium You are given an array of integers `stones` where `stones[i]` is the weight of the ith stone. We are playing a game with the stones. On each turn, we choose any two stones and smash them together. Suppose the stones have weights `x` and `y` with `x <= y`. The result of this smash is: * If `x == y`, both stones are destroyed, and * If `x != y`, the stone of weight `x` is destroyed, and the stone of weight `y` has new weight `y - x`. At the end of the game, there is **at most one** stone left. Return _the smallest possible weight of the left stone_. If there are no stones left, return `0`. **Example 1:** **Input:** stones = [2,7,4,1,8,1] **Output:** 1 **Explanation:** We can combine 2 and 4 to get 2, so the array converts to [2,7,1,8,1] then, we can combine 7 and 8 to get 1, so the array converts to [2,1,1,1] then, we can combine 2 and 1 to get 1, so the array converts to [1,1,1] then, we can combine 1 and 1 to get 0, so the array converts to [1], then that's the optimal value. **Example 2:** **Input:** stones = [31,26,33,21,40] **Output:** 5 **Constraints:** * `1 <= stones.length <= 30` * `1 <= stones[i] <= 100`
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • lastStoneWeightII

      public int lastStoneWeightII(int[] stones)