java.lang.Object
g1301_1400.s1383_maximum_performance_of_a_team.Solution

public class Solution extends Object
1383 - Maximum Performance of a Team\. Hard You are given two integers `n` and `k` and two integer arrays `speed` and `efficiency` both of length `n`. There are `n` engineers numbered from `1` to `n`. `speed[i]` and `efficiency[i]` represent the speed and efficiency of the ith engineer respectively. Choose **at most** `k` different engineers out of the `n` engineers to form a team with the maximum **performance**. The performance of a team is the sum of their engineers' speeds multiplied by the minimum efficiency among their engineers. Return _the maximum performance of this team_. Since the answer can be a huge number, return it **modulo** 109 + 7. **Example 1:** **Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2 **Output:** 60 **Explanation:** We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) \* min(4, 7) = 60. **Example 2:** **Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3 **Output:** 68 **Explanation:** This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) \* min(5, 4, 7) = 68. **Example 3:** **Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4 **Output:** 72 **Constraints:** * 1 <= k <= n <= 105 * `speed.length == n` * `efficiency.length == n` * 1 <= speed[i] <= 105 * 1 <= efficiency[i] <= 108
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maxPerformance

      public int maxPerformance(int n, int[] speed, int[] efficiency, int k)