Class Solution
java.lang.Object
g1301_1400.s1383_maximum_performance_of_a_team.Solution
1383 - Maximum Performance of a Team\.
Hard
You are given two integers `n` and `k` and two integer arrays `speed` and `efficiency` both of length `n`. There are `n` engineers numbered from `1` to `n`. `speed[i]` and `efficiency[i]` represent the speed and efficiency of the
ith
engineer respectively.
Choose **at most** `k` different engineers out of the `n` engineers to form a team with the maximum **performance**.
The performance of a team is the sum of their engineers' speeds multiplied by the minimum efficiency among their engineers.
Return _the maximum performance of this team_. Since the answer can be a huge number, return it **modulo** 109 + 7
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**Example 1:**
**Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2
**Output:** 60
**Explanation:**
We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) \* min(4, 7) = 60.
**Example 2:**
**Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3
**Output:** 68
**Explanation:**
This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) \* min(5, 4, 7) = 68.
**Example 3:**
**Input:** n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4
**Output:** 72
**Constraints:**
* 1 <= k <= n <= 105
* `speed.length == n`
* `efficiency.length == n`
* 1 <= speed[i] <= 105
* 1 <= efficiency[i] <= 108
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Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionint
maxPerformance
(int n, int[] speed, int[] efficiency, int k)
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Constructor Details
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Solution
public Solution()
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Method Details
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maxPerformance
public int maxPerformance(int n, int[] speed, int[] efficiency, int k)
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