Class Solution

java.lang.Object
g1501_1600.s1529_bulb_switcher_iv.Solution

public class Solution extends Object
1529 - Minimum Suffix Flips\. Medium You are given a **0-indexed** binary string `target` of length `n`. You have another binary string `s` of length `n` that is initially set to all zeros. You want to make `s` equal to `target`. In one operation, you can pick an index `i` where `0 <= i < n` and flip all bits in the **inclusive** range `[i, n - 1]`. Flip means changing `'0'` to `'1'` and `'1'` to `'0'`. Return _the minimum number of operations needed to make_ `s` _equal to_ `target`. **Example 1:** **Input:** target = "10111" **Output:** 3 **Explanation:** Initially, s = "00000". Choose index i = 2: "00000" -> "00111" Choose index i = 0: "00111" -> "11000" Choose index i = 1: "11000" -> "10111" We need at least 3 flip operations to form target. **Example 2:** **Input:** target = "101" **Output:** 3 **Explanation:** Initially, s = "000". Choose index i = 0: "000" -> "111" Choose index i = 1: "111" -> "100" Choose index i = 2: "100" -> "101" We need at least 3 flip operations to form target. **Example 3:** **Input:** target = "00000" **Output:** 0 **Explanation:** We do not need any operations since the initial s already equals target. **Constraints:** * `n == target.length` * 1 <= n <= 105 * `target[i]` is either `'0'` or `'1'`.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • minFlips

      public int minFlips(String target)