Class Solution
java.lang.Object
g1601_1700.s1680_concatenation_of_consecutive_binary_numbers.Solution
1680 - Concatenation of Consecutive Binary Numbers\.
Medium
Given an integer `n`, return _the **decimal value** of the binary string formed by concatenating the binary representations of_ `1` _to_ `n` _in order, **modulo**_
109 + 7
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**Example 1:**
**Input:** n = 1
**Output:** 1
**Explanation:** "1" in binary corresponds to the decimal value 1.
**Example 2:**
**Input:** n = 3
**Output:** 27
**Explanation:** In binary, 1, 2, and 3 corresponds to "1", "10", and "11".
After concatenating them, we have "11011", which corresponds to the decimal value 27.
**Example 3:**
**Input:** n = 12
**Output:** 505379714
**Explanation:** The concatenation results in "1101110010111011110001001101010111100".
The decimal value of that is 118505380540.
After modulo 109 + 7, the result is 505379714.
**Constraints:**
* 1 <= n <= 105
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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concatenatedBinary
public int concatenatedBinary(int n)
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