java.lang.Object
g1701_1800.s1702_maximum_binary_string_after_change.Solution

public class Solution extends Object
1702 - Maximum Binary String After Change\. Medium You are given a binary string `binary` consisting of only `0`'s or `1`'s. You can apply each of the following operations any number of times: * Operation 1: If the number contains the substring `"00"`, you can replace it with `"10"`. * For example, `"00010" -> "10010`" * Operation 2: If the number contains the substring `"10"`, you can replace it with `"01"`. * For example, `"00010" -> "00001"` _Return the **maximum binary string** you can obtain after any number of operations. Binary string `x` is greater than binary string `y` if `x`'s decimal representation is greater than `y`'s decimal representation._ **Example 1:** **Input:** binary = "000110" **Output:** "111011" **Explanation:** A valid transformation sequence can be: "000110" -> "000101" "000101" -> "100101" "100101" -> "110101" "110101" -> "110011" "110011" -> "111011" **Example 2:** **Input:** binary = "01" **Output:** "01" **Explanation:** "01" cannot be transformed any further. **Constraints:** * 1 <= binary.length <= 105 * `binary` consist of `'0'` and `'1'`.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maximumBinaryString

      public String maximumBinaryString(String binary)