java.lang.Object
g1701_1800.s1705_maximum_number_of_eaten_apples.Solution

public class Solution extends Object
1705 - Maximum Number of Eaten Apples\. Medium There is a special kind of apple tree that grows apples every day for `n` days. On the ith day, the tree grows `apples[i]` apples that will rot after `days[i]` days, that is on day `i + days[i]` the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by `apples[i] == 0` and `days[i] == 0`. You decided to eat **at most** one apple a day (to keep the doctors away). Note that you can keep eating after the first `n` days. Given two integer arrays `days` and `apples` of length `n`, return _the maximum number of apples you can eat._ **Example 1:** **Input:** apples = [1,2,3,5,2], days = [3,2,1,4,2] **Output:** 7 **Explanation:** You can eat 7 apples: - On the first day, you eat an apple that grew on the first day. - On the second day, you eat an apple that grew on the second day. - On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot. - On the fourth to the seventh days, you eat apples that grew on the fourth day. **Example 2:** **Input:** apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2] **Output:** 5 **Explanation:** You can eat 5 apples: - On the first to the third day you eat apples that grew on the first day. - Do nothing on the fouth and fifth days. - On the sixth and seventh days you eat apples that grew on the sixth day. **Constraints:** * `n == apples.length == days.length` * 1 <= n <= 2 * 104 * 0 <= apples[i], days[i] <= 2 * 104 * `days[i] = 0` if and only if `apples[i] = 0`.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • eatenApples

      public int eatenApples(int[] apples, int[] days)