Class Solution
java.lang.Object
g1701_1800.s1749_maximum_absolute_sum_of_any_subarray.Solution
1749 - Maximum Absolute Sum of Any Subarray\.
Medium
You are given an integer array `nums`. The **absolute sum** of a subarray
[numsl, numsl+1, ..., numsr-1, numsr]
is abs(numsl + numsl+1 + ... + numsr-1 + numsr)
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Return _the **maximum** absolute sum of any **(possibly empty)** subarray of_ `nums`.
Note that `abs(x)` is defined as follows:
* If `x` is a negative integer, then `abs(x) = -x`.
* If `x` is a non-negative integer, then `abs(x) = x`.
**Example 1:**
**Input:** nums = [1,-3,2,3,-4]
**Output:** 5
**Explanation:** The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.
**Example 2:**
**Input:** nums = [2,-5,1,-4,3,-2]
**Output:** 8
**Explanation:** The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.
**Constraints:**
* 1 <= nums.length <= 105
* -104 <= nums[i] <= 104
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Constructor Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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maxAbsoluteSum
public int maxAbsoluteSum(int[] nums)
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