java.lang.Object
g1901_2000.s1962_remove_stones_to_minimize_the_total.Solution

public class Solution extends Object
1962 - Remove Stones to Minimize the Total\. Medium You are given a **0-indexed** integer array `piles`, where `piles[i]` represents the number of stones in the ith pile, and an integer `k`. You should apply the following operation **exactly** `k` times: * Choose any `piles[i]` and **remove** `floor(piles[i] / 2)` stones from it. **Notice** that you can apply the operation on the **same** pile more than once. Return _the **minimum** possible total number of stones remaining after applying the_ `k` _operations_. `floor(x)` is the **greatest** integer that is **smaller** than or **equal** to `x` (i.e., rounds `x` down). **Example 1:** **Input:** piles = [5,4,9], k = 2 **Output:** 12 **Explanation:** Steps of a possible scenario are: - Apply the operation on pile 2. The resulting piles are [5,4,5]. - Apply the operation on pile 0. The resulting piles are [3,4,5]. The total number of stones in [3,4,5] is 12. **Example 2:** **Input:** piles = [4,3,6,7], k = 3 **Output:** 12 **Explanation:** Steps of a possible scenario are: - Apply the operation on pile 2. The resulting piles are [4,3,3,7]. - Apply the operation on pile 3. The resulting piles are [4,3,3,4]. - Apply the operation on pile 0. The resulting piles are [2,3,3,4]. The total number of stones in [2,3,3,4] is 12. **Constraints:** * 1 <= piles.length <= 105 * 1 <= piles[i] <= 104 * 1 <= k <= 105
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • minStoneSum

      public int minStoneSum(int[] piles, int k)