java.lang.Object
g2001_2100.s2012_sum_of_beauty_in_the_array.Solution

public class Solution extends Object
2012 - Sum of Beauty in the Array\. Medium You are given a **0-indexed** integer array `nums`. For each index `i` (`1 <= i <= nums.length - 2`) the **beauty** of `nums[i]` equals: * `2`, if `nums[j] < nums[i] < nums[k]`, for **all** `0 <= j < i` and for **all** `i < k <= nums.length - 1`. * `1`, if `nums[i - 1] < nums[i] < nums[i + 1]`, and the previous condition is not satisfied. * `0`, if none of the previous conditions holds. Return _the **sum of beauty** of all_ `nums[i]` _where_ `1 <= i <= nums.length - 2`. **Example 1:** **Input:** nums = [1,2,3] **Output:** 2 **Explanation:** For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 2. **Example 2:** **Input:** nums = [2,4,6,4] **Output:** 1 **Explanation:** For each index i in the range 1 <= i <= 2: - The beauty of nums[1] equals 1. - The beauty of nums[2] equals 0. **Example 3:** **Input:** nums = [3,2,1] **Output:** 0 **Explanation:** For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 0. **Constraints:** * 3 <= nums.length <= 105 * 1 <= nums[i] <= 105
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • sumOfBeauties

      public int sumOfBeauties(int[] nums)