Package g2101_2200.s2121_intervals_between_identical_elements

Class Solution

java.lang.Object
g2101_2200.s2121_intervals_between_identical_elements.Solution
public class Solution extends Object
2121 - Intervals Between Identical Elements\. Medium You are given a **0-indexed** array of `n` integers `arr`. The **interval** between two elements in `arr` is defined as the **absolute difference** between their indices. More formally, the **interval** between `arr[i]` and `arr[j]` is `|i - j|`. Return _an array_ `intervals` _of length_ `n` _where_ `intervals[i]` _is **the sum of intervals** between_ `arr[i]` _and each element in_ `arr` _with the same value as_ `arr[i]`_._ **Note:** `|x|` is the absolute value of `x`. **Example 1:** **Input:** arr = [2,1,3,1,2,3,3] **Output:** [4,2,7,2,4,4,5] **Explanation:** - Index 0: Another 2 is found at index 4. |0 - 4| = 4 - Index 1: Another 1 is found at index 3. |1 - 3| = 2 - Index 2: Two more 3s are found at indices 5 and 6. |2 - 5| + |2 - 6| = 7 - Index 3: Another 1 is found at index 1. |3 - 1| = 2 - Index 4: Another 2 is found at index 0. |4 - 0| = 4 - Index 5: Two more 3s are found at indices 2 and 6. |5 - 2| + |5 - 6| = 4 - Index 6: Two more 3s are found at indices 2 and 5. |6 - 2| + |6 - 5| = 5 **Example 2:** **Input:** arr = [10,5,10,10] **Output:** [5,0,3,4] **Explanation:** - Index 0: Two more 10s are found at indices 2 and 3. |0 - 2| + |0 - 3| = 5 - Index 1: There is only one 5 in the array, so its sum of intervals to identical elements is 0. - Index 2: Two more 10s are found at indices 0 and 3. |2 - 0| + |2 - 3| = 3 - Index 3: Two more 10s are found at indices 0 and 2. |3 - 0| + |3 - 2| = 4 **Constraints:** * `n == arr.length` * 1 <= n <= 105 * 1 <= arr[i] <= 105

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • getDistances

      public long[] getDistances(int[] arr)