Class Solution
java.lang.Object
g2101_2200.s2156_find_substring_with_given_hash_value.Solution
2156 - Find Substring With Given Hash Value\.
Hard
The hash of a **0-indexed** string `s` of length `k`, given integers `p` and `m`, is computed using the following function:
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hash(s, p, m) = (val(s[0]) * p0 + val(s[1]) * p1 + ... + val(s[k-1]) * pk-1) mod m
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Where `val(s[i])` represents the index of `s[i]` in the alphabet from `val('a') = 1` to `val('z') = 26`.
You are given a string `s` and the integers `power`, `modulo`, `k`, and `hashValue.` Return `sub`, _the **first** **substring** of_ `s` _of length_ `k` _such that_ `hash(sub, power, modulo) == hashValue`.
The test cases will be generated such that an answer always **exists**.
A **substring** is a contiguous non-empty sequence of characters within a string.
**Example 1:**
**Input:** s = "leetcode", power = 7, modulo = 20, k = 2, hashValue = 0
**Output:** "ee"
**Explanation:** The hash of "ee" can be computed to be hash("ee", 7, 20) = (5 \* 1 + 5 \* 7) mod 20 = 40 mod 20 = 0. "ee" is the first substring of length 2 with hashValue 0. Hence, we return "ee".
**Example 2:**
**Input:** s = "fbxzaad", power = 31, modulo = 100, k = 3, hashValue = 32
**Output:** "fbx"
**Explanation:** The hash of "fbx" can be computed to be hash("fbx", 31, 100) = (6 \* 1 + 2 \* 31 + 24 \* 312) mod 100 = 23132 mod 100 = 32.
The hash of "bxz" can be computed to be hash("bxz", 31, 100) = (2 \* 1 + 24 \* 31 + 26 \* 312) mod 100 = 25732 mod 100 = 32. "fbx" is the first substring of length 3 with hashValue 32. Hence, we return "fbx".
Note that "bxz" also has a hash of 32 but it appears later than "fbx".
**Constraints:**
* 1 <= k <= s.length <= 2 * 104
* 1 <= power, modulo <= 109
* `0 <= hashValue < modulo`
* `s` consists of lowercase English letters only.
* The test cases are generated such that an answer always **exists**.-
Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionsubStrHash
(String s, int power, int modulo, int k, int hashValue)
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Constructor Details
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Solution
public Solution()
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Method Details
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subStrHash
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