java.lang.Object
g2301_2400.s2398_maximum_number_of_robots_within_budget.Solution

public class Solution extends Object
2398 - Maximum Number of Robots Within Budget\. Hard You have `n` robots. You are given two **0-indexed** integer arrays, `chargeTimes` and `runningCosts`, both of length `n`. The ith robot costs `chargeTimes[i]` units to charge and costs `runningCosts[i]` units to run. You are also given an integer `budget`. The **total cost** of running `k` chosen robots is equal to `max(chargeTimes) + k * sum(runningCosts)`, where `max(chargeTimes)` is the largest charge cost among the `k` robots and `sum(runningCosts)` is the sum of running costs among the `k` robots. Return _the **maximum** number of **consecutive** robots you can run such that the total cost **does not** exceed_ `budget`. **Example 1:** **Input:** chargeTimes = [3,6,1,3,4], runningCosts = [2,1,3,4,5], budget = 25 **Output:** 3 **Explanation:** It is possible to run all individual and consecutive pairs of robots within budget. To obtain answer 3, consider the first 3 robots. The total cost will be max(3,6,1) + 3 \* sum(2,1,3) = 6 + 3 \* 6 = 24 which is less than 25. It can be shown that it is not possible to run more than 3 consecutive robots within budget, so we return 3. **Example 2:** **Input:** chargeTimes = [11,12,19], runningCosts = [10,8,7], budget = 19 **Output:** 0 **Explanation:** No robot can be run that does not exceed the budget, so we return 0. **Constraints:** * `chargeTimes.length == runningCosts.length == n` * 1 <= n <= 5 * 104 * 1 <= chargeTimes[i], runningCosts[i] <= 105 * 1 <= budget <= 1015
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maximumRobots

      public int maximumRobots(int[] chargeTimes, int[] runningCosts, long budget)