Class Solution
java.lang.Object
g2301_2400.s2398_maximum_number_of_robots_within_budget.Solution
2398 - Maximum Number of Robots Within Budget\.
Hard
You have `n` robots. You are given two **0-indexed** integer arrays, `chargeTimes` and `runningCosts`, both of length `n`. The
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robot costs `chargeTimes[i]` units to charge and costs `runningCosts[i]` units to run. You are also given an integer `budget`.
The **total cost** of running `k` chosen robots is equal to `max(chargeTimes) + k * sum(runningCosts)`, where `max(chargeTimes)` is the largest charge cost among the `k` robots and `sum(runningCosts)` is the sum of running costs among the `k` robots.
Return _the **maximum** number of **consecutive** robots you can run such that the total cost **does not** exceed_ `budget`.
**Example 1:**
**Input:** chargeTimes = [3,6,1,3,4], runningCosts = [2,1,3,4,5], budget = 25
**Output:** 3
**Explanation:**
It is possible to run all individual and consecutive pairs of robots within budget.
To obtain answer 3, consider the first 3 robots. The total cost will be max(3,6,1) + 3 \* sum(2,1,3) = 6 + 3 \* 6 = 24 which is less than 25.
It can be shown that it is not possible to run more than 3 consecutive robots within budget, so we return 3.
**Example 2:**
**Input:** chargeTimes = [11,12,19], runningCosts = [10,8,7], budget = 19
**Output:** 0
**Explanation:** No robot can be run that does not exceed the budget, so we return 0.
**Constraints:**
* `chargeTimes.length == runningCosts.length == n`
* 1 <= n <= 5 * 104
* 1 <= chargeTimes[i], runningCosts[i] <= 105
* 1 <= budget <= 1015
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Constructor Summary
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Method Summary
Modifier and TypeMethodDescriptionint
maximumRobots
(int[] chargeTimes, int[] runningCosts, long budget)
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Constructor Details
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Solution
public Solution()
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Method Details
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maximumRobots
public int maximumRobots(int[] chargeTimes, int[] runningCosts, long budget)
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