Class Solution
java.lang.Object
g2501_2600.s2578_split_with_minimum_sum.Solution
2578 - Split With Minimum Sum.
Easy
Given a positive integer num
, split it into two non-negative integers num1
and num2
such that:
- The concatenation of
num1
andnum2
is a permutation ofnum
.- In other words, the sum of the number of occurrences of each digit in
num1
andnum2
is equal to the number of occurrences of that digit innum
.
- In other words, the sum of the number of occurrences of each digit in
num1
andnum2
can contain leading zeros.
Return the minimum possible sum of num1
and num2
.
Notes:
- It is guaranteed that
num
does not contain any leading zeros. - The order of occurrence of the digits in
num1
andnum2
may differ from the order of occurrence ofnum
.
Example 1:
Input: num = 4325
Output: 59
Explanation: We can split 4325 so that num1
is 24 and num2 is
35, giving a sum of 59. We can prove that 59 is indeed the minimal possible sum.
Example 2:
Input: num = 687
Output: 75
Explanation: We can split 687 so that num1
is 68 and num2
is 7, which would give an optimal sum of 75.
Constraints:
10 <= num <= 109
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Constructor Summary
Constructors -
Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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splitNum
public int splitNum(int number)
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