g0001_0100.s0087_scramble_string.Solution

public class Solution extends Object

87 - Scramble String.Hard We can scramble a string s to get a string t using the following algorithm: <ol> <li>If the length of the string is 1, stop.</li> <li>If the length of the string is > 1, do the following: <ul> <li>Split the string into two non-empty substrings at a random index, i.e., if the string is <code>s</code>, divide it to <code>x</code> and <code>y</code> where <code>s = x + y</code>.</li> <li>Randomly decide to swap the two substrings or to keep them in the same order. i.e., after this step, <code>s</code> may become <code>s = x + y</code> or <code>s = y + x</code>.</li> <li>Apply step 1 recursively on each of the two substrings <code>x</code> and <code>y</code>.</li> </ul> </li> </ol> Given two strings <code>s1</code> and <code>s2</code> of the same length , return <code>true</code> if <code>s2</code> is a scrambled string of <code>s1</code>, otherwise, return <code>false</code>. Example 1: Input: s1 = “great”, s2 = “rgeat” Output: true Explanation: One possible scenario applied on s1 is: “great” –> “gr/eat” // divide at random index. “gr/eat” –> “gr/eat” // random decision is not to swap the two substrings and keep them in order. “gr/eat” –> “g/r / e/at” // apply the same algorithm recursively on both substrings. divide at ranom index each of them. “g/r / e/at” –> “r/g / e/at” // random decision was to swap the first substring and to keep the second substring in the same order. “r/g / e/at” –> “r/g / e/ a/t” // again apply the algorithm recursively, divide “at” to “a/t”. “r/g / e/ a/t” –> “r/g / e/ a/t” // random decision is to keep both substrings in the same order. The algorithm stops now and the result string is “rgeat” which is s2. As there is one possible scenario that led s1 to be scrambled to s2, we return true. Example 2: Input: s1 = “abcde”, s2 = “caebd” Output: false Example 3: Input: s1 = “a”, s2 = “a” Output: true Constraints: <ul> <li><code>s1.length == s2.length</code></li> <li><code>1 <= s1.length <= 30</code></li> <li><code>s1</code> and <code>s2</code> consist of lower-case English letters.</li> </ul>

Constructor Summary

Constructors

Constructor

Description

Solution()
Method Summary

Modifier and Type

Method

Description

boolean

isScramble(String s1, String s2)

Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details
- Solution
  
  public Solution()
Method Details
- isScramble
  
  public boolean isScramble(String s1, String s2)

Class Solution

Constructor Summary

Method Summary

Methods inherited from class java.lang.Object

Constructor Details

Solution

Method Details

isScramble