Class Solution

java.lang.Object
g0101_0200.s0127_word_ladder.Solution

public class Solution extends Object
127 - Word Ladder.<p>Hard</p> <p>A <strong>transformation sequence</strong> from word <code>beginWord</code> to word <code>endWord</code> using a dictionary <code>wordList</code> is a sequence of words <code>beginWord -> s<sub>1</sub> -> s<sub>2</sub> -> &hellip; -> s<sub>k</sub></code> such that:</p> <ul> <li>Every adjacent pair of words differs by a single letter.</li> <li>Every <code>s<sub>i</sub></code> for <code>1 <= i <= k</code> is in <code>wordList</code>. Note that <code>beginWord</code> does not need to be in <code>wordList</code>.</li> <li><code>s<sub>k</sub> == endWord</code></li> </ul> <p>Given two words, <code>beginWord</code> and <code>endWord</code>, and a dictionary <code>wordList</code>, return <em>the <strong>number of words</strong> in the <strong>shortest transformation sequence</strong> from</em> <code>beginWord</code> <em>to</em> <code>endWord</code><em>, or</em> <code>0</code> <em>if no such sequence exists.</em></p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> beginWord = &ldquo;hit&rdquo;, endWord = &ldquo;cog&rdquo;, wordList = [&ldquo;hot&rdquo;,&ldquo;dot&rdquo;,&ldquo;dog&rdquo;,&ldquo;lot&rdquo;,&ldquo;log&rdquo;,&ldquo;cog&rdquo;]</p> <p><strong>Output:</strong> 5</p> <p><strong>Explanation:</strong> One shortest transformation sequence is &ldquo;hit&rdquo; -> &ldquo;hot&rdquo; -> &ldquo;dot&rdquo; -> &ldquo;dog&rdquo; -> cog&quot;, which is 5 words long.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> beginWord = &ldquo;hit&rdquo;, endWord = &ldquo;cog&rdquo;, wordList = [&ldquo;hot&rdquo;,&ldquo;dot&rdquo;,&ldquo;dog&rdquo;,&ldquo;lot&rdquo;,&ldquo;log&rdquo;]</p> <p><strong>Output:</strong> 0</p> <p><strong>Explanation:</strong> The endWord &ldquo;cog&rdquo; is not in wordList, therefore there is no valid transformation sequence.</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= beginWord.length <= 10</code></li> <li><code>endWord.length == beginWord.length</code></li> <li><code>1 <= wordList.length <= 5000</code></li> <li><code>wordList[i].length == beginWord.length</code></li> <li><code>beginWord</code>, <code>endWord</code>, and <code>wordList[i]</code> consist of lowercase English letters.</li> <li><code>beginWord != endWord</code></li> <li>All the words in <code>wordList</code> are <strong>unique</strong>.</li> </ul>
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    • Solution

      public Solution()
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