Package g0101_0200.s0140_word_break_ii
Class Solution
java.lang.Object
g0101_0200.s0140_word_break_ii.Solution
140 - Word Break II.<p>Hard</p>
<p>Given a string <code>s</code> and a dictionary of strings <code>wordDict</code>, add spaces in <code>s</code> to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in <strong>any order</strong>.</p>
<p><strong>Note</strong> that the same word in the dictionary may be reused multiple times in the segmentation.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> s = “catsanddog”, wordDict = [“cat”,“cats”,“and”,“sand”,“dog”]</p>
<p><strong>Output:</strong> [“cats and dog”,“cat sand dog”]</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> s = “pineapplepenapple”, wordDict = [“apple”,“pen”,“applepen”,“pine”,“pineapple”]</p>
<p><strong>Output:</strong> [“pine apple pen apple”,“pineapple pen apple”,“pine applepen apple”]</p>
<p><strong>Explanation:</strong> Note that you are allowed to reuse a dictionary word.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> s = “catsandog”, wordDict = [“cats”,“dog”,“sand”,“and”,“cat”]</p>
<p><strong>Output:</strong> []</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= s.length <= 20</code></li>
<li><code>1 <= wordDict.length <= 1000</code></li>
<li><code>1 <= wordDict[i].length <= 10</code></li>
<li><code>s</code> and <code>wordDict[i]</code> consist of only lowercase English letters.</li>
<li>All the strings of <code>wordDict</code> are <strong>unique</strong>.</li>
</ul>
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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wordBreak
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