Class Solution
java.lang.Object
g0101_0200.s0145_binary_tree_postorder_traversal.Solution
145 - Binary Tree Postorder Traversal.<p>Easy</p>
<p>Given the <code>root</code> of a binary tree, return <em>the postorder traversal of its nodes’ values</em>.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/08/28/pre1.jpg" alt="" /></p>
<p><strong>Input:</strong> root = [1,null,2,3]</p>
<p><strong>Output:</strong> [3,2,1]</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> root = []</p>
<p><strong>Output:</strong> []</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> root = [1]</p>
<p><strong>Output:</strong> [1]</p>
<p><strong>Example 4:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/08/28/pre3.jpg" alt="" /></p>
<p><strong>Input:</strong> root = [1,2]</p>
<p><strong>Output:</strong> [2,1]</p>
<p><strong>Example 5:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/08/28/pre2.jpg" alt="" /></p>
<p><strong>Input:</strong> root = [1,null,2]</p>
<p><strong>Output:</strong> [2,1]</p>
<p><strong>Constraints:</strong></p>
<ul>
<li>The number of the nodes in the tree is in the range <code>[0, 100]</code>.</li>
<li><code>-100 <= Node.val <= 100</code></li>
</ul>
<p><strong>Follow up:</strong> Recursive solution is trivial, could you do it iteratively?</p>
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Solution
public Solution()
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postorderTraversal
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