Package g0301_0400.s0396_rotate_function

Class Solution

java.lang.Object

g0301_0400.s0396_rotate_function.Solution

public class Solution
extends Object

396 - Rotate Function.<p>Medium</p> <p>You are given an integer array <code>nums</code> of length <code>n</code>.</p> <p>Assume <code>arr_k</code> to be an array obtained by rotating <code>nums</code> by <code>k</code> positions clock-wise. We define the <strong>rotation function</strong> <code>F</code> on <code>nums</code> as follow:</p> <ul> <li><code>F(k) = 0 * arr_k[0] + 1 * arr_k[1] + &hellip; + (n - 1) * arr_k[n - 1].</code></li> </ul> <p>Return <em>the maximum value of</em> <code>F(0), F(1), ..., F(n-1)</code>.</p> <p>The test cases are generated so that the answer fits in a <strong>32-bit</strong> integer.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> nums = [4,3,2,6]</p> <p><strong>Output:</strong> 26</p> <p><strong>Explanation:</strong></p> <p>F(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18 = 25</p> <p>F(1) = (0 * 6) + (1 * 4) + (2 * 3) + (3 * 2) = 0 + 4 + 6 + 6 = 16</p> <p>F(2) = (0 * 2) + (1 * 6) + (2 * 4) + (3 * 3) = 0 + 6 + 8 + 9 = 23</p> <p>F(3) = (0 * 3) + (1 * 2) + (2 * 6) + (3 * 4) = 0 + 2 + 12 + 12 = 26</p> <p>So the maximum value of F(0), F(1), F(2), F(3) is F(3) = 26.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> nums = [100]</p> <p><strong>Output:</strong> 0</p> <p><strong>Constraints:</strong></p> <ul> <li><code>n == nums.length</code></li> <li><code>1 <= n <= 10⁵</code></li> <li><code>-100 <= nums[i] <= 100</code></li> </ul>

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
int	maxRotateFunction(int[] nums)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

maxRotateFunction

public int maxRotateFunction(int[] nums)