Class Solution
java.lang.Object
g0401_0500.s0414_third_maximum_number.Solution
414 - Third Maximum Number.<p>Easy</p>
<p>Given an integer array <code>nums</code>, return <em>the <strong>third distinct maximum</strong> number in this array. If the third maximum does not exist, return the <strong>maximum</strong> number</em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> nums = [3,2,1]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Explanation:</strong> The first distinct maximum is 3. The second distinct maximum is 2. The third distinct maximum is 1.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> nums = [1,2]</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> The first distinct maximum is 2. The second distinct maximum is 1. The third distinct maximum does not exist, so the maximum (2) is returned instead.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> nums = [2,2,3,1]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Explanation:</strong> The first distinct maximum is 3. The second distinct maximum is 2 (both 2’s are counted together since they have the same value). The third distinct maximum is 1.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>
<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>
</ul>
<p><strong>Follow up:</strong> Can you find an <code>O(n)</code> solution?</p>
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Solution
public Solution()
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Method Details
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thirdMax
public int thirdMax(int[] nums)
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