Class Solution
java.lang.Object
g0501_0600.s0590_n_ary_tree_postorder_traversal.Solution
590 - N-ary Tree Postorder Traversal.<p>Easy</p>
<p>Given the <code>root</code> of an n-ary tree, return <em>the postorder traversal of its nodes’ values</em>.</p>
<p>Nary-Tree input serialization is represented in their level order traversal. Each group of children is separated by the null value (See examples)</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png" alt="" /></p>
<p><strong>Input:</strong> root = [1,null,3,2,4,null,5,6]</p>
<p><strong>Output:</strong> [5,6,3,2,4,1]</p>
<p><strong>Example 2:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png" alt="" /></p>
<p><strong>Input:</strong> root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]</p>
<p><strong>Output:</strong> [2,6,14,11,7,3,12,8,4,13,9,10,5,1]</p>
<p><strong>Constraints:</strong></p>
<ul>
<li>The number of nodes in the tree is in the range <code>[0, 10<sup>4</sup>]</code>.</li>
<li><code>0 <= Node.val <= 10<sup>4</sup></code></li>
<li>The height of the n-ary tree is less than or equal to <code>1000</code>.</li>
</ul>
<p><strong>Follow up:</strong> Recursive solution is trivial, could you do it iteratively?</p>
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Solution
public Solution()
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postorder
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