Class Solution
java.lang.Object
g0601_0700.s0636_exclusive_time_of_functions.Solution
636 - Exclusive Time of Functions.<p>Medium</p>
<p>On a <strong>single-threaded</strong> CPU, we execute a program containing <code>n</code> functions. Each function has a unique ID between <code>0</code> and <code>n-1</code>.</p>
<p>Function calls are <strong>stored in a <a href="https://en.wikipedia.org/wiki/Call_stack" target="_top">call stack</a></strong>: when a function call starts, its ID is pushed onto the stack, and when a function call ends, its ID is popped off the stack. The function whose ID is at the top of the stack is <strong>the current function being executed</strong>. Each time a function starts or ends, we write a log with the ID, whether it started or ended, and the timestamp.</p>
<p>You are given a list <code>logs</code>, where <code>logs[i]</code> represents the <code>i<sup>th</sup></code> log message formatted as a string <code>"{function_id}:{"start" | "end"}:{timestamp}"</code>. For example, <code>"0:start:3"</code> means a function call with function ID <code>0</code> <strong>started at the beginning</strong> of timestamp <code>3</code>, and <code>"1:end:2"</code> means a function call with function ID <code>1</code> <strong>ended at the end</strong> of timestamp <code>2</code>. Note that a function can be called <strong>multiple times, possibly recursively</strong>.</p>
<p>A function’s <strong>exclusive time</strong> is the sum of execution times for all function calls in the program. For example, if a function is called twice, one call executing for <code>2</code> time units and another call executing for <code>1</code> time unit, the <strong>exclusive time</strong> is <code>2 + 1 = 3</code>.</p>
<p>Return <em>the <strong>exclusive time</strong> of each function in an array, where the value at the</em> <code>i<sup>th</sup></code> <em>index represents the exclusive time for the function with ID</em> <code>i</code>.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2019/04/05/diag1b.png" alt="" /></p>
<p><strong>Input:</strong> n = 2, logs = [“0:start:0”,“1:start:2”,“1:end:5”,“0:end:6”]</p>
<p><strong>Output:</strong> [3,4]</p>
<p><strong>Explanation:</strong></p>
<p>Function 0 starts at the beginning of time 0, then it executes 2 for units of time and reaches the end of time 1.</p>
<p>Function 1 starts at the beginning of time 2, executes for 4 units of time, and ends at the end of time 5.</p>
<p>Function 0 resumes execution at the beginning of time 6 and executes for 1 unit of time.</p>
<p>So function 0 spends 2 + 1 = 3 units of total time executing, and function 1 spends 4 units of total time executing.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> n = 1, logs = [“0:start:0”,“0:start:2”,“0:end:5”,“0:start:6”,“0:end:6”,“0:end:7”]</p>
<p><strong>Output:</strong> [8]</p>
<p><strong>Explanation:</strong></p>
<p>Function 0 starts at the beginning of time 0, executes for 2 units of time, and recursively calls itself.</p>
<p>Function 0 (recursive call) starts at the beginning of time 2 and executes for 4 units of time.</p>
<p>Function 0 (initial call) resumes execution then immediately calls itself again.</p>
<p>Function 0 (2nd recursive call) starts at the beginning of time 6 and executes for 1 unit of time.</p>
<p>Function 0 (initial call) resumes execution at the beginning of time 7 and executes for 1 unit of time.</p>
<p>So function 0 spends 2 + 4 + 1 + 1 = 8 units of total time executing.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> n = 2, logs = [“0:start:0”,“0:start:2”,“0:end:5”,“1:start:6”,“1:end:6”,“0:end:7”]</p>
<p><strong>Output:</strong> [7,1]</p>
<p><strong>Explanation:</strong></p>
<p>Function 0 starts at the beginning of time 0, executes for 2 units of time, and recursively calls itself.</p>
<p>Function 0 (recursive call) starts at the beginning of time 2 and executes for 4 units of time.</p>
<p>Function 0 (initial call) resumes execution then immediately calls function 1.</p>
<p>Function 1 starts at the beginning of time 6, executes 1 unit of time, and ends at the end of time 6.</p>
<p>Function 0 resumes execution at the beginning of time 6 and executes for 2 units of time.</p>
<p>So function 0 spends 2 + 4 + 1 = 7 units of total time executing, and function 1 spends 1 unit of total time executing.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= n <= 100</code></li>
<li><code>1 <= logs.length <= 500</code></li>
<li><code>0 <= function_id < n</code></li>
<li><code>0 <= timestamp <= 10<sup>9</sup></code></li>
<li>No two start events will happen at the same timestamp.</li>
<li>No two end events will happen at the same timestamp.</li>
<li>Each function has an <code>"end"</code> log for each <code>"start"</code> log.</li>
</ul>
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Solution
public Solution()
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exclusiveTime
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