Package g0701_0800.s0786_k_th_smallest_prime_fraction

Class Solution

java.lang.Object
g0701_0800.s0786_k_th_smallest_prime_fraction.Solution
public class Solution extends Object
786 - K-th Smallest Prime Fraction.<p>Hard</p> <p>You are given a sorted integer array <code>arr</code> containing <code>1</code> and <strong>prime</strong> numbers, where all the integers of <code>arr</code> are unique. You are also given an integer <code>k</code>.</p> <p>For every <code>i</code> and <code>j</code> where <code>0 <= i < j < arr.length</code>, we consider the fraction <code>arr[i] / arr[j]</code>.</p> <p>Return <em>the</em> <code>k<sup>th</sup></code> <em>smallest fraction considered</em>. Return your answer as an array of integers of size <code>2</code>, where <code>answer[0] == arr[i]</code> and <code>answer[1] == arr[j]</code>.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> arr = [1,2,3,5], k = 3</p> <p><strong>Output:</strong> [2,5]</p> <p><strong>Explanation:</strong></p> <pre><code> The fractions to be considered in sorted order are: 1/5, 1/3, 2/5, 1/2, 3/5, and 2/3. The third fraction is 2/5. </code></pre> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> arr = [1,7], k = 1</p> <p><strong>Output:</strong> [1,7]</p> <p><strong>Constraints:</strong></p> <ul> <li><code>2 <= arr.length <= 1000</code></li> <li><code>1 <= arr[i] <= 3 * 10<sup>4</sup></code></li> <li><code>arr[0] == 1</code></li> <li><code>arr[i]</code> is a <strong>prime</strong> number for <code>i > 0</code>.</li> <li>All the numbers of <code>arr</code> are <strong>unique</strong> and sorted in <strong>strictly increasing</strong> order.</li> <li><code>1 <= k <= arr.length * (arr.length - 1) / 2</code></li> </ul>

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • kthSmallestPrimeFraction

      public int[] kthSmallestPrimeFraction(int[] arr, int k)