Package g0801_0900.s0851_loud_and_rich
Class Solution
java.lang.Object
g0801_0900.s0851_loud_and_rich.Solution
851 - Loud and Rich.<p>Medium</p>
<p>There is a group of <code>n</code> people labeled from <code>0</code> to <code>n - 1</code> where each person has a different amount of money and a different level of quietness.</p>
<p>You are given an array <code>richer</code> where <code>richer[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> indicates that <code>a<sub>i</sub></code> has more money than <code>b<sub>i</sub></code> and an integer array <code>quiet</code> where <code>quiet[i]</code> is the quietness of the <code>i<sup>th</sup></code> person. All the given data in richer are <strong>logically correct</strong> (i.e., the data will not lead you to a situation where <code>x</code> is richer than <code>y</code> and <code>y</code> is richer than <code>x</code> at the same time).</p>
<p>Return <em>an integer array</em> <code>answer</code> <em>where</em> <code>answer[x] = y</code> <em>if</em> <code>y</code> <em>is the least quiet person (that is, the person</em> <code>y</code> <em>with the smallest value of</em> <code>quiet[y]</code><em>) among all people who definitely have equal to or more money than the person</em> <code>x</code>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]</p>
<p><strong>Output:</strong> [5,5,2,5,4,5,6,7]</p>
<p><strong>Explanation:</strong></p>
<p>answer[0] = 5.</p>
<p>Person 5 has more money than 3, which has more money than 1, which has more money than 0.</p>
<p>The only person who is quieter (has lower quiet[x]) is person 7, but it is not clear if they have more money than person 0.</p>
<p>answer[7] = 7.</p>
<p>Among all people that definitely have equal to or more money than person 7 (which could be persons 3, 4, 5, 6, or 7), the person who is the quietest (has lower quiet[x]) is person 7.</p>
<p>The other answers can be filled out with similar reasoning.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> richer = [], quiet = [0]</p>
<p><strong>Output:</strong> [0]</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == quiet.length</code></li>
<li><code>1 <= n <= 500</code></li>
<li><code>0 <= quiet[i] < n</code></li>
<li>All the values of <code>quiet</code> are <strong>unique</strong>.</li>
<li><code>0 <= richer.length <= n * (n - 1) / 2</code></li>
<li><code>0 <= a<sub>i</sub>, b<sub>i</sub> < n</code></li>
<li><code>a<sub>i</sub> != b<sub>i</sub></code></li>
<li>All the pairs of <code>richer</code> are <strong>unique</strong>.</li>
<li>The observations in <code>richer</code> are all logically consistent.</li>
</ul>
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Solution
public Solution()
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loudAndRich
public int[] loudAndRich(int[][] richer, int[] quiet)
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