Package g0801_0900.s0899_orderly_queue

Class Solution

java.lang.Object

g0801_0900.s0899_orderly_queue.Solution

public class Solution
extends Object

899 - Orderly Queue.<p>Hard</p> <p>You are given a string <code>s</code> and an integer <code>k</code>. You can choose one of the first <code>k</code> letters of <code>s</code> and append it at the end of the string..</p> <p>Return <em>the lexicographically smallest string you could have after applying the mentioned step any number of moves</em>.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> s = &ldquo;cba&rdquo;, k = 1</p> <p><strong>Output:</strong> &ldquo;acb&rdquo;</p> <p><strong>Explanation:</strong></p> <p>In the first move, we move the 1^st character &lsquo;c&rsquo; to the end, obtaining the string &ldquo;bac&rdquo;.</p> <p>In the second move, we move the 1^st character &lsquo;b&rsquo; to the end, obtaining the final result &ldquo;acb&rdquo;.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> s = &ldquo;baaca&rdquo;, k = 3</p> <p><strong>Output:</strong> &ldquo;aaabc&rdquo;</p> <p><strong>Explanation:</strong></p> <p>In the first move, we move the 1^st character &lsquo;b&rsquo; to the end, obtaining the string &ldquo;aacab&rdquo;.</p> <p>In the second move, we move the 3^rd character &lsquo;c&rsquo; to the end, obtaining the final result &ldquo;aaabc&rdquo;.</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= k <= s.length <= 1000</code></li> <li><code>s</code> consist of lowercase English letters.</li> </ul>

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
String	orderlyQueue(String s, int k)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

orderlyQueue

public String orderlyQueue(String s,
 int k)