Class Solution
java.lang.Object
g1401_1500.s1401_circle_and_rectangle_overlapping.Solution
1401 - Circle and Rectangle Overlapping.<p>Medium</p>
<p>You are given a circle represented as <code>(radius, xCenter, yCenter)</code> and an axis-aligned rectangle represented as <code>(x1, y1, x2, y2)</code>, where <code>(x1, y1)</code> are the coordinates of the bottom-left corner, and <code>(x2, y2)</code> are the coordinates of the top-right corner of the rectangle.</p>
<p>Return <code>true</code> <em>if the circle and rectangle are overlapped otherwise return</em> <code>false</code>. In other words, check if there is <strong>any</strong> point <code>(x<sub>i</sub>, y<sub>i</sub>)</code> that belongs to the circle and the rectangle at the same time.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/02/20/sample_4_1728.png" alt="" /></p>
<p><strong>Input:</strong> radius = 1, xCenter = 0, yCenter = 0, x1 = 1, y1 = -1, x2 = 3, y2 = 1</p>
<p><strong>Output:</strong> true</p>
<p><strong>Explanation:</strong> Circle and rectangle share the point (1,0).</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> radius = 1, xCenter = 1, yCenter = 1, x1 = 1, y1 = -3, x2 = 2, y2 = -1</p>
<p><strong>Output:</strong> false</p>
<p><strong>Example 3:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/02/20/sample_2_1728.png" alt="" /></p>
<p><strong>Input:</strong> radius = 1, xCenter = 0, yCenter = 0, x1 = -1, y1 = 0, x2 = 0, y2 = 1</p>
<p><strong>Output:</strong> true</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= radius <= 2000</code></li>
<li><code>-10<sup>4</sup> <= xCenter, yCenter <= 10<sup>4</sup></code></li>
<li><code>-10<sup>4</sup> <= x1 < x2 <= 10<sup>4</sup></code></li>
<li><code>-10<sup>4</sup> <= y1 < y2 <= 10<sup>4</sup></code></li>
</ul>
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Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionboolean
checkOverlap
(int radius, int xCenter, int yCenter, int x1, int y1, int x2, int y2)
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Constructor Details
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Solution
public Solution()
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Method Details
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checkOverlap
public boolean checkOverlap(int radius, int xCenter, int yCenter, int x1, int y1, int x2, int y2)
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