Package g1501_1600.s1592_rearrange_spaces_between_words

Class Solution

java.lang.Object
g1501_1600.s1592_rearrange_spaces_between_words.Solution
public class Solution extends Object
1592 - Rearrange Spaces Between Words.<p>Easy</p> <p>You are given a string <code>text</code> of words that are placed among some number of spaces. Each word consists of one or more lowercase English letters and are separated by at least one space. It&rsquo;s guaranteed that <code>text</code> <strong>contains at least one word</strong>.</p> <p>Rearrange the spaces so that there is an <strong>equal</strong> number of spaces between every pair of adjacent words and that number is <strong>maximized</strong>. If you cannot redistribute all the spaces equally, place the <strong>extra spaces at the end</strong> , meaning the returned string should be the same length as <code>text</code>.</p> <p>Return <em>the string after rearranging the spaces</em>.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> text = &quot; this is a sentence &quot;</p> <p><strong>Output:</strong> &ldquo;this is a sentence&rdquo;</p> <p><strong>Explanation:</strong> There are a total of 9 spaces and 4 words. We can evenly divide the 9 spaces between the words: 9 / (4-1) = 3 spaces.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> text = &quot; practice makes perfect&quot;</p> <p><strong>Output:</strong> &quot;practice makes perfect &quot;</p> <p><strong>Explanation:</strong> There are a total of 7 spaces and 3 words. 7 / (3-1) = 3 spaces plus 1 extra space. We place this extra space at the end of the string.</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= text.length <= 100</code></li> <li><code>text</code> consists of lowercase English letters and <code>' '</code>.</li> <li><code>text</code> contains at least one word.</li> </ul>

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