Class Solution
java.lang.Object
g1601_1700.s1653_minimum_deletions_to_make_string_balanced.Solution
1653 - Minimum Deletions to Make String Balanced.<p>Medium</p>
<p>You are given a string <code>s</code> consisting only of characters <code>'a'</code> and <code>'b'</code>.</p>
<p>You can delete any number of characters in <code>s</code> to make <code>s</code> <strong>balanced</strong>. <code>s</code> is <strong>balanced</strong> if there is no pair of indices <code>(i,j)</code> such that <code>i < j</code> and <code>s[i] = 'b'</code> and <code>s[j]= 'a'</code>.</p>
<p>Return <em>the <strong>minimum</strong> number of deletions needed to make</em> <code>s</code> <em><strong>balanced</strong></em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> s = “aababbab”</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> You can either:</p>
<p>Delete the characters at 0-indexed positions 2 and 6 (“aababbab” -> “aaabbb”), or</p>
<p>Delete the characters at 0-indexed positions 3 and 6 (“aababbab” -> “aabbbb”).</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> s = “bbaaaaabb”</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> The only solution is to delete the first two characters.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= s.length <= 10<sup>5</sup></code></li>
<li><code>s[i]</code> is <code>'a'</code> or <code>'b'</code>.</li>
</ul>
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Solution
public Solution()
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minimumDeletions
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