Package g1601_1700.s1680_concatenation_of_consecutive_binary_numbers

Class Solution

java.lang.Object

g1601_1700.s1680_concatenation_of_consecutive_binary_numbers.Solution

public class Solution
extends Object

1680 - Concatenation of Consecutive Binary Numbers.<p>Medium</p> <p>Given an integer <code>n</code>, return <em>the <strong>decimal value</strong> of the binary string formed by concatenating the binary representations of</em> <code>1</code> <em>to</em> <code>n</code> <em>in order, <strong>modulo</strong></em> <code>10⁹ + 7</code>.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> n = 1</p> <p><strong>Output:</strong> 1</p> <p><strong>Explanation:</strong> &ldquo;1&rdquo; in binary corresponds to the decimal value 1.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> n = 3</p> <p><strong>Output:</strong> 27</p> <p><strong>Explanation:</strong> In binary, 1, 2, and 3 corresponds to &ldquo;1&rdquo;, &ldquo;10&rdquo;, and &ldquo;11&rdquo;.</p> <p>After concatenating them, we have &ldquo;11011&rdquo;, which corresponds to the decimal value 27.</p> <p><strong>Example 3:</strong></p> <p><strong>Input:</strong> n = 12</p> <p><strong>Output:</strong> 505379714</p> <p><strong>Explanation:</strong> The concatenation results in &ldquo;1101110010111011110001001101010111100&rdquo;.</p> <p>The decimal value of that is 118505380540.</p> <p>After modulo 10⁹ + 7, the result is 505379714.</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= n <= 10⁵</code></li> </ul>

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
int	concatenatedBinary(int n)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

concatenatedBinary

public int concatenatedBinary(int n)