Class Solution
java.lang.Object
g1901_2000.s1991_find_the_middle_index_in_array.Solution
1991 - Find the Middle Index in Array.<p>Easy</p>
<p>Given a <strong>0-indexed</strong> integer array <code>nums</code>, find the <strong>leftmost</strong> <code>middleIndex</code> (i.e., the smallest amongst all the possible ones).</p>
<p>A <code>middleIndex</code> is an index where <code>nums[0] + nums[1] + ... + nums[middleIndex-1] == nums[middleIndex+1] + nums[middleIndex+2] + ... + nums[nums.length-1]</code>.</p>
<p>If <code>middleIndex == 0</code>, the left side sum is considered to be <code>0</code>. Similarly, if <code>middleIndex == nums.length - 1</code>, the right side sum is considered to be <code>0</code>.</p>
<p>Return <em>the <strong>leftmost</strong></em> <code>middleIndex</code> <em>that satisfies the condition, or</em> <code>-1</code> <em>if there is no such index</em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> nums = [2,3,-1,8,4]</p>
<p><strong>Output:</strong> 3</p>
<p><strong>Explanation:</strong> The sum of the numbers before index 3 is: 2 + 3 + -1 = 4</p>
<p>The sum of the numbers after index 3 is: 4 = 4</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> nums = [1,-1,4]</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> The sum of the numbers before index 2 is: 1 + -1 = 0</p>
<p>The sum of the numbers after index 2 is: 0</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> nums = [2,5]</p>
<p><strong>Output:</strong> -1</p>
<p><strong>Explanation:</strong> There is no valid middleIndex.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nums.length <= 100</code></li>
<li><code>-1000 <= nums[i] <= 1000</code></li>
</ul>
<p><strong>Note:</strong> This question is the same as 724</p>
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Solution
public Solution()
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findMiddleIndex
public int findMiddleIndex(int[] nums)
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