Class Solution
java.lang.Object
g2201_2300.s2221_find_triangular_sum_of_an_array.Solution
2221 - Find Triangular Sum of an Array.<p>Medium</p>
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>, where <code>nums[i]</code> is a digit between <code>0</code> and <code>9</code> ( <strong>inclusive</strong> ).</p>
<p>The <strong>triangular sum</strong> of <code>nums</code> is the value of the only element present in <code>nums</code> after the following process terminates:</p>
<ol>
<li>Let <code>nums</code> comprise of <code>n</code> elements. If <code>n == 1</code>, <strong>end</strong> the process. Otherwise, <strong>create</strong> a new <strong>0-indexed</strong> integer array <code>newNums</code> of length <code>n - 1</code>.</li>
<li>For each index <code>i</code>, where <code>0 <= i < n - 1</code>, <strong>assign</strong> the value of <code>newNums[i]</code> as <code>(nums[i] + nums[i+1]) % 10</code>, where <code>%</code> denotes modulo operator.</li>
<li><strong>Replace</strong> the array <code>nums</code> with <code>newNums</code>.</li>
<li><strong>Repeat</strong> the entire process starting from step 1.</li>
</ol>
<p>Return <em>the triangular sum of</em> <code>nums</code>.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2022/02/22/ex1drawio.png" alt="" /></p>
<p><strong>Input:</strong> nums = [1,2,3,4,5]</p>
<p><strong>Output:</strong> 8</p>
<p><strong>Explanation:</strong> The above diagram depicts the process from which we obtain the triangular sum of the array.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> nums = [5]</p>
<p><strong>Output:</strong> 5</p>
<p><strong>Explanation:</strong> Since there is only one element in nums, the triangular sum is the value of that element itself.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nums.length <= 1000</code></li>
<li><code>0 <= nums[i] <= 9</code></li>
</ul>
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Solution
public Solution()
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Method Details
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triangularSum
public int triangularSum(int[] nums)
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