Class Solution
Medium
Given a list of strings words
and a string pattern
, return a list of words[i]
that match pattern
. You may return the answer in any order.
A word matches the pattern if there exists a permutation of letters p
so that after replacing every letter x
in the pattern with p(x)
, we get the desired word.
Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.
Example 1:
Input: words = [“abc”,“deq”,“mee”,“aqq”,“dkd”,“ccc”], pattern = “abb”
Output: [“mee”,“aqq”]
Explanation: “mee” matches the pattern because there is a permutation {a -> m, b -> e, …}. “ccc” does not match the pattern because {a -> c, b -> c, …} is not a permutation, since a and b map to the same letter.
Example 2:
Input: words = [“a”,“b”,“c”], pattern = “a”
Output: [“a”,“b”,“c”]
Constraints:
1 <= pattern.length <= 20
1 <= words.length <= 50
words[i].length == pattern.length
pattern
andwords[i]
are lowercase English letters.
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Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionjava.util.List
<java.lang.String> findAndReplacePattern
(java.lang.String[] words, java.lang.String pattern) Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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findAndReplacePattern
public java.util.List<java.lang.String> findAndReplacePattern(java.lang.String[] words, java.lang.String pattern)
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