Class Solution
java.lang.Object
g2801_2900.s2864_maximum_odd_binary_number.Solution
public class Solution
extends java.lang.Object
2864 - Maximum Odd Binary Number.
Easy
You are given a binary string s
that contains at least one '1'
.
You have to rearrange the bits in such a way that the resulting binary number is the maximum odd binary number that can be created from this combination.
Return a string representing the maximum odd binary number that can be created from the given combination.
Note that the resulting string can have leading zeros.
Example 1:
Input: s = “010”
Output: “001”
Explanation: Because there is just one ‘1’, it must be in the last position. So the answer is “001”.
Example 2:
Input: s = “0101”
Output: “1001”
Explanation: One of the ’1’s must be in the last position. The maximum number that can be made with the remaining digits is “100”. So the answer is “1001”.
Constraints:
1 <= s.length <= 100
s
consists only of'0'
and'1'
.s
contains at least one'1'
.
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Constructor Summary
Constructors -
Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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maximumOddBinaryNumber
public java.lang.String maximumOddBinaryNumber(java.lang.String s)
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