Package g0501_0600.s0522_longest_uncommon_subsequence_ii

Class Solution

java.lang.Object
g0501_0600.s0522_longest_uncommon_subsequence_ii.Solution
public class Solution extends java.lang.Object
522 - Longest Uncommon Subsequence II.

Medium

Given an array of strings strs, return the length of the longest uncommon subsequence between them. If the longest uncommon subsequence does not exist, return -1.

An uncommon subsequence between an array of strings is a string that is a subsequence of one string but not the others.

A subsequence of a string s is a string that can be obtained after deleting any number of characters from s.

  • For example, "abc" is a subsequence of "aebdc" because you can delete the underlined characters in "aebdc" to get "abc". Other subsequences of "aebdc" include "aebdc", "aeb", and "" (empty string).

Example 1:

Input: strs = [“aba”,“cdc”,“eae”]

Output: 3

Example 2:

Input: strs = [“aaa”,“aaa”,“aa”]

Output: -1

Constraints:

  • 2 <= strs.length <= 50
  • 1 <= strs[i].length <= 10
  • strs[i] consists of lowercase English letters.

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int
    findLUSlength(java.lang.String[] strs)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • findLUSlength

      public int findLUSlength(java.lang.String[] strs)