Class Solution
Hard
Given a string s, return the number of different non-empty palindromic subsequences in s
. Since the answer may be very large, return it modulo 109 + 7
.
A subsequence of a string is obtained by deleting zero or more characters from the string.
A sequence is palindromic if it is equal to the sequence reversed.
Two sequences a1, a2, …
and b1, b2, …
are different if there is some i
for which ai != bi
.
Example 1:
Input: s = “bccb”
Output: 6
Explanation: The 6 different non-empty palindromic subsequences are ‘b’, ‘c’, ‘bb’, ‘cc’, ‘bcb’, ‘bccb’. Note that ‘bcb’ is counted only once, even though it occurs twice.
Example 2:
Input: s = “abcdabcdabcdabcdabcdabcdabcdabcddcbadcbadcbadcbadcbadcbadcbadcba”
Output: 104860361
Explanation: There are 3104860382 different non-empty palindromic subsequences, which is 104860361 modulo 109 + 7.
Constraints:
1 <= s.length <= 1000
s[i]
is either'a'
,'b'
,'c'
, or'd'
.
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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countPalindromicSubsequences
public int countPalindromicSubsequences(java.lang.String s)
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